MCQ
If $3^\text{x}=64=2^6+(\sqrt{3})^8,$ then the value of $x$ is:
- A$2$
- B$1$
- ✓$4$
- D$3$
✓
Answer
Correct option: C.
$4$
$3^\text{x+64}=2^6+(\sqrt{3})^8$
But we know that,
$2^6=64$
So, $2^6+3^\text{x}=2^6+(\sqrt{3})^{2\times4}$
$\Rightarrow2^6+3\text{x}=2^6+(3)^4$
Now by equating both
We get,
$\text{x}=4$
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