MCQ
If $-3x + 17 < - 13,$ then
  • $x \in(10, \infty)$
  • B
    $x \in[10, \infty)$
  • C
    $x \in(-\infty, 10)$
  • D
    $x \in[-10,10)$

Answer

Correct option: A.
$x \in(10, \infty)$
(A) $x \in(10, \infty)$
Explanation: Given,
$- 3x + 17 < - 13$
$\Rightarrow$ $- 3x < - 17 - 13$
$\Rightarrow$ $- 3x < - 30$
$\Rightarrow$ $3x > 30$
$\Rightarrow$ $x > 10$
$\Rightarrow$ $x \in(10, \infty)$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free