MCQ
If ${{3x + 4} \over {{x^2} - 3x + 2}} = {A \over {x - 2}} - {B \over {x - 1}}$,then $(A,\,B) = $
- A$(7, 10)$
- ✓$(10, 7)$
- C$(10, -7)$
- D$(-10, 7)$
$ \Rightarrow $ $3=A-B,$ $4 = - A + 2B$
$ \Rightarrow $ $A = 10,\,\,\,B = 7$
$\therefore (A,\,B) = (10,\,7)$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Match the Statements / Expressions in Column $I$ with the Statements / Expressions in Column $II$ and indicate your answer by darkening the appropriate bubbles in the $4 \times 4$ matrix given in the $ORS.$
| Column $I$ | Column $II$ |
| $(A)$ $ \mathrm{L}_1, \mathrm{~L}_2, \mathrm{~L}_3$ are concurrent, if | $(p)$ $\mathrm{k}=-9$ |
| $(B)$ One of $\mathrm{L}_1, \mathrm{~L}_2, \mathrm{~L}_3$ is parallel to at least one of the other two, if | $(q)$ $\mathrm{k}=-\frac{6}{5}$ |
| $(C)$ $\mathrm{L}_1, \mathrm{~L}_2, \mathrm{~L}_3$ form a triangle, if | $(r)$ $\mathrm{k}=\frac{5}{6}$ |
| $(D)$ $ \mathrm{L}_1, \mathrm{~L}_2, \mathrm{~L}_3$ do not form a triangle, if | $(s)$ $\mathrm{k}=5$ |