MCQ
If $4.0 \,gm $ $NaOH$ is present in $1$ litre solution, then its $pH$ will be
- A$6$
- ✓$13$
- C$18$
- D$24$
$[O{H^ - }] = {10^{ - 1}}M$, $[{H^ + }] = {10^{ - 13}}M$, $pH = 13$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
${I^ - }(aq.) + MnO_4^ - (aq.)\xrightarrow[{weakly\,\,O{H^ - }}]{{Neutral\,\,or}}Y + Mn{O_2}$
$MnO_4^ - (aq.) + M{n^{2 + }}(aq.)\xrightarrow{{ZnS{O_4}}}Z + 4{H^ + }$
Products $X,\,Y$ and $Z$ are respectively :
