- A$-6$
- B$-8$
- ✓$-10$
- D$-12$
or $(4i + j - k)\,.\,(3i + mj + 2k) = 0$
or $12 + m - 2 = 0$ or $m = - 10.$
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$x+y+z=5$ ; $x+2 y+3 z=\mu$ ; $x+3 y+\lambda z=1$
is constructed. If $\mathrm{p}$ is the probability that the system has a unique solution and $\mathrm{q}$ is the probability that the system has no solution, then :
$\frac{1}{2}$
$\frac{1}{4}$
$\frac{1}{6}$
$\text{None of these}$
$\vec{\text{a}}+\vec{\text{b}}$
$\vec{\text{a}}-\vec{\text{b}}$
$\vec{\text{b}}-\vec{\text{a}}$
$-\big(\vec{\text{a}}+\vec{\text{b}}\big)$
$\alpha \log _{\mathrm{e}}|1+\tan \mathrm{x}|+\beta \log _{\mathrm{c}}\left|1-\tan \mathrm{x}+\tan ^{2} \mathrm{x}\right|+\gamma \tan ^{-1}\left(\frac{2 \tan \mathrm{x}-1}{\sqrt{3}}\right)+\mathrm{C}$
when $\mathrm{C}$ is constant of integration, then the value of $18\left(\alpha+\beta+\gamma^{2}\right)$ is .... .
$\int\left(\left(\frac{x}{e}\right)^{2 x}+\left(\frac{e}{x}\right)^{2 x}\right) \log _{ e } x d x=\frac{1}{\alpha}\left(\frac{ x }{ e }\right)^{\beta x}-\frac{1}{\gamma}\left(\frac{ e }{ x }\right)^{\delta x }+ C ,$
Where $e =\sum \limits_{ n =0}^{\infty} \frac{1}{ n !}$ and $C$ is constant of integration, then $\alpha+2 \beta+3 \gamma-4 \delta$ is equal to: