MCQ
If $4\tan\theta = 3$ then $\frac{4\sin\theta-\cos\theta}{{4\sin\theta+\cos\theta}}$ is equal to :
- A$\frac{3}{4}$
- ✓$\frac{1}{2}$
- C$\frac{1}{3}$
- D$\frac{2}{3}$
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