Question
If $a = 3$ and $b = -2,$ find the values of : $a + b^{ab}$
✓
Answer
We have,
$a^b + b^a$
$= (3 + (-2))^{3(-2)}$
$= (3 − 2)^{-6}$
$= (1)^{−6} $
$= 1$
$a^b + b^a$
$= (3 + (-2))^{3(-2)}$
$= (3 − 2)^{-6}$
$= (1)^{−6} $
$= 1$
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