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Playing with Numbers — MATHS STD 8 — Question

ICSE BoardEnglish MediumSTD 8MATHSPlaying with Numbers1 Mark
MCQ
If $A + A + A = BI$, where $A$ and $B$ are different digits, then
  • A
    $A = 1, B = 5$
  • B
    $A = 5, B = 2$
  • ✓
    $A = 5, B = 1$
  • D
    $A = 7, B = 2$
✓

Answer

Correct option: C.
$A = 5, B = 1$
$A+A+A=B I$, where $A$ and $B$ are different digits then $A=7, B=2$.
As unit digit of sum $=1$
$\therefore$ A will be $\frac{21}{3}=7$
$\left\{\because \frac{11}{3}, \frac{31}{3}\right.$ are not naturals $\}$
$\therefore A=7, B=2$ 

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