Download App

Sets — Maths STD 11 Science — Question

CBSE BoardEnglish MediumSTD 11 ScienceMathsSets1 Mark
MCQ
If A and B are two given sets, then $\text{A}\cap\text{(A}\cap\text{B})^\text{c}$ is equal to:
  • A
    $\text{A}$
  • B
    $\text{B}$
  • C
    $\phi$
  • ✓
    $\text{A}\cap\text{B}^\text{c}.$
✓

Answer

Correct option: D.
$\text{A}\cap\text{B}^\text{c}.$
A and B are two sets.
$\text{A}\cap\text{B}$ is the common region in both the sets.
$\text{A}\cap\text{B}^\text{c}$ is all the region in the universal set except $\text{A}\cap\text{B}.$
Now,
$\text{(A}\cap\text{A}\cap\text{B)}^\text{c}=\text{(A}\cap\text{B)}^\text{c}.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Sets→Sets — all question types→Maths STD 11 Science question papers→CBSE Board STD 11 Science question papers→CBSE Board question paper generator→

Similar questions

While shuffling a pack of $52$ playing cards, $2$ are accidentally dropped. Find the probability that the missing cards to be of different colours:
→
If $x^n - 1$ is divisible by $x - k,$ then the least positive integral value of $k$ is:
→
Sum of values of $'k'$ for which image of point $(\lambda^2 + 1,\lambda )$ with respect to line $y = -3x + 6k$ is the point $(\lambda,\lambda-1)$, is-
→
The given circle $x^2 + y^2 + 2px = 0$, $p\ \in\ R$  touches the parabola $y^2 = 4x$  externally, then
→
Which of the following is not a negation of “A natural number is greater than zero”.
→
A variable line $ax + by + c = 0$, where $a, b, c$ are in $A.P.$, is normal to a circle $(x - \alpha)^2 + (y - \beta)^2 = \gamma$ , which is orthogonal to circle $x^2 + y^2- 4x- 4y-1 = 0$. The value of $\alpha + \beta + \gamma$ is equal to
→
The circle passing through the distinct points $(1, t) , (t, 1)\, \& \,(t, t)$ for all values of $' t '$ , passes through the point :
→
Let $x, y, z$  be positive real numbers such that $x + y + z = 12$ and  $x^3y^4z^5 = (0. 1 ) (600)^3$. Then $x^3 + y^3 + z^3$ is equal to
→
If $P(3, 2, -4), Q(5, 4, -6)$ and $R(9, 8, -10)$ are collinear, then $R$ divides $PQ$ in the ratio:
→
Let $\mathrm{z}=\frac{1-i \sqrt{3}}{2}, i=\sqrt{-1} .$ Then the value of

$21+\left(z+\frac{1}{z}\right)^{3}+\left(z^{2}+\frac{1}{z^{2}}\right)^{3}+\left(z^{3}+\frac{1}{z^{3}}\right)^{3}+\ldots+\left(z^{21}+\frac{1}{z^{21}}\right)^{3}$ is .... .

→