Question
If $A \cap B=\emptyset$ and $P(A \cap B’)= 0.48,$ then find $P(A).$

Answer

$P(A)$ $= P(A \cap B') + P(A \cap B)$  
  $= 0.48 + 0$
  $= 0.48$
$\therefore$ Value of $P(A) = 0.48.$  

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