Question
If $A \cap B=\emptyset$ and $P(A \cap B’)= 0.48,$ then find $P(A).$
| $P(A)$ | $= P(A \cap B') + P(A \cap B)$ | |
| $= 0.48 + 0$ | ||
| $= 0.48$ | ||
| $\therefore$ Value of $P(A) = 0.48.$ | ||
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.