If A + B = [ * 20 c 1&0 1&1 ]and A - 2B = [ * 20 c - 1 &1 0& - 1 … - Vidyadip

MCQ

If $A + B = \left[ {\begin{array}{*{20}{c}}1&0\\1&1\end{array}} \right]$and $A - 2B = \left[ {\begin{array}{*{20}{c}}{ - 1}&1\\0&{ - 1}\end{array}} \right]\,,$ then $A=$

A
$\left[ {\begin{array}{*{20}{c}}1&1\\2&1\end{array}} \right]$
B
$\left[ {\begin{array}{*{20}{c}}{2/3}&{1/3}\\{1/3}&{2/3}\end{array}} \right]$
✓
$\left[ {\begin{array}{*{20}{c}}{1/3}&{1/3}\\{2/3}&{1/3}\end{array}} \right]$
D
None of these

✓

Answer

Correct option: C.

$\left[ {\begin{array}{*{20}{c}}{1/3}&{1/3}\\{2/3}&{1/3}\end{array}} \right]$

c
(c) $2A + 2B = \left[ {\begin{array}{*{20}{c}}2&0\\2&2\end{array}} \right]$, $A - 2B = \left[ {\begin{array}{*{20}{c}}{ - 1}&1\\0&{ - 1}\end{array}} \right]$

On adding, we get$3A = \left[ {\begin{array}{*{20}{c}}1&1\\2&1\end{array}} \right]$

$ \Rightarrow \,A = \left[ {\begin{array}{*{20}{c}}{1/3}&{1/3}\\{2/3}&{1/3}\end{array}} \right]$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 3 and 4 . determinant and metrices→3 and 4 . determinant and metrices — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

The differential equation $2xy\,\, dy = (x^2 + y^2 + 1) dx$ determines

If $m$ is a non-zero number and $\int \frac{x^{5 m-1}+2 x^{4 m-1}}{\left(x^{2 m}+x^{m}+1\right)^{3}} d x=f(x)+c$ , then $f(x)$ is

If $I = \int\limits_0^{\frac{\pi }{2}} {\,\,\ell n\,(\sin \,x)} dx$ then $\int\limits_{\frac{{ - \pi }}{4}}^{\frac{\pi }{4}} {\,\,\ell n\,(\sin \,x\,\, + \,\,\cos \,x)} dx =$

The solution of the differential equation $3{e^x}\tan ydx + (1 - {e^x}){\sec ^2}ydy = 0$ is

$\int_{}^{} {\frac{{x + 1}}{{\sqrt {1 + {x^2}} }}dx} = $

Let $N$ be the set of positive integers. For all $n \in N$, let $f_n=(n+1)^{1 / 3}-n^{1 / 3} \text { and }$ $A=\left\{n \in N: f_{n+1}<\frac{1}{3(n+1)^{2 / 3}} < f_n\right\}$ Then,

One maximum point of ${\sin ^p}x{\cos ^q}x$ is

The area between x-axis and curve $\text{y}=\cos\text{x}$ when $0\leq\text{x}\leq2\pi$ is:

0
2
3
4

If the vectors, $\overrightarrow{\mathrm{p}}=(a+1) \hat{\mathrm{i}}+a \hat{\mathrm{j}}+a \hat{\mathrm{k}}$ ; $\overrightarrow{\mathrm{q}}=\mathrm{a} \hat{\mathrm{i}}+(\mathrm{a}+1) \hat{\mathrm{j}}+\mathrm{a} \hat{\mathrm{k}}$ and $\overrightarrow{\mathrm{r}}=\mathrm{a} \hat{\mathrm{i}}+\mathrm{a} \hat{\mathrm{j}}+(\mathrm{a}+1) \hat{\mathrm{k}}(\mathrm{a} \in \mathrm{R})$ are coplanar and $3(\overrightarrow{\mathrm{p}} \cdot \overrightarrow{\mathrm{q}})^{2}-\lambda|\overrightarrow{\mathrm{r}} \times \overrightarrow{\mathrm{q}}|^{2}=0,$ then the value of $\lambda$ is

Assume that $f$ is continuous everywhere, then $\frac{1}{c}\int_{ac}^{bc} {f\left( {\frac{x}{c}} \right)} \,dx = $