Question
If $a: b=4: 7$, find the following:
$\frac{6 a-b}{a+3 b}$

Answer

$a: b=4: 7 \Rightarrow \frac{a}{b}=\frac{4}{7} $
$\frac{6 a-b}{a+3 b}=\frac{6 \frac{a}{b}-1}{\frac{a}{b}+3}$
$ =\frac{6 \times \frac{4}{7}-1}{\frac{4}{7}+3} $
$=\frac{\frac{24}{7}-1}{\frac{4}{7}+3} $
$ =\frac{17}{25}$

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