Question
If $A$ is a square symmetric matrix, then $A ^{ T }=$_____

Answer

self

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Based on the above information, answer the following questions.
  1. Both the circular pieces of cardboard meet each other at
  1. $\text{x}=1$
  2. $\text{x}=\frac{1}{2}$
  3. $\text{x}=\frac{1}{3}$
  4. $\text{x}=\frac{1}{4}$
  1. Graph of given two curves can be drawn as.
  1. None of these
  1. Value of $\int\limits_{0}^{\frac{1}{2}}\sqrt{1-(\text{x}-1)^2}\text{dx}$ is.
  1. $\frac{\pi}{6}-\frac{\sqrt{3}}{8}$
  2. $\frac{\pi}{6}+\frac{\sqrt{3}}{8}$
  3. $\frac{\pi}{2}+\frac{\sqrt{3}}{4}$
  4. $\frac{\pi}{2}-\frac{\sqrt{3}}{4}$
  1. Value of $\int\limits_{\frac{1}{2}}^{1}\sqrt{1-\text{x}^2}\text{dx}$ is.
  1. $\frac{\pi}{6}+\frac{\sqrt{3}}{4}$
  2. $\frac{\pi}{6}+\frac{\sqrt{3}}{8}$
  3. $\frac{\pi}{6}-\frac{\sqrt{3}}{8}$
  4. $\frac{\pi}{2}-\frac{\sqrt{3}}{4}$
  1. Area of hidden portion of lower circle is.
  1. $\bigg(\frac{2\pi}{3}+\frac{\sqrt{3}}{2}\bigg)\text{ sq.units}$
  2. $\bigg(\frac{\pi}{3}-\frac{\sqrt{3}}{8}\bigg)\text{ sq.units}$
  3. $\bigg(\frac{\pi}{3}+\frac{\sqrt{3}}{8}\bigg)\text{ sq.units}$
  4. $\bigg(\frac{2\pi}{3}-\frac{\sqrt{3}}{2}\bigg)\text{ sq.units}$