MCQ
If $A = \left[ {\begin{array}{*{20}{c}}
a&0&0\\
0&a&0\\
0&0&a
\end{array}} \right]$ ; then $|A| |adjA|$ is equal to
a&0&0\\
0&a&0\\
0&0&a
\end{array}} \right]$ ; then $|A| |adjA|$ is equal to
- A$a^{25}$
- B$a^{27}$
- C$a^{81}$
- ✓$a^9$
$\Rightarrow|\mathrm{A}||\operatorname{adj} \mathrm{A}|=\mathrm{a}^{9}$
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The solution of the differential equation $\frac{\text{dy}}{\text{dx}}+\frac{2\text{xy}}{1+\text{x}^2}=\frac{1}{(1+\text{x}^2)^2}$ is:
$\text{y}(1+\text{x}^2)=\text{C}+\tan^{-1}\text{x}$
$\frac{\text{y}}{1+\text{x}^2}=\text{C}+\tan^{-1}\text{x}$
$\text{y}\log(1+\text{x}^2)=\text{C}+\tan^{-1}\text{x}$
$\text{y}(1+\text{x}^2)=\text{C}+\sin^{-1}\text{x}$