Download App

3 and 4 . determinant and metrices — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMaths3 and 4 . determinant and metrices1 Mark
MCQ
If $A = \left[ {\begin{array}{*{20}{c}}0&1\\0&0\end{array}} \right]$and $AB = O$, then $B =$
  • A
    $\left[ {\begin{array}{*{20}{c}}1&1\\1&1\end{array}} \right]$
  • B
    $\left[ {\begin{array}{*{20}{c}}0&1\\{ - 1}&0\end{array}} \right]$
  • C
    $\left[ {\begin{array}{*{20}{c}}0&{ - 1}\\1&0\end{array}} \right]$
  • ✓
    $\left[ {\begin{array}{*{20}{c}}{ - 1}&0\\0&0\end{array}} \right]$
✓

Answer

Correct option: D.
$\left[ {\begin{array}{*{20}{c}}{ - 1}&0\\0&0\end{array}} \right]$
d
(d) Since $\left[ {\begin{array}{*{20}{c}}0&1\\0&0\end{array}} \right]\,\left[ {\begin{array}{*{20}{c}}{ - 1}&0\\0&0\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}0&0\\0&0\end{array}} \right] = O = AB$
==> $B = \left[ {\begin{array}{*{20}{c}}{ - 1}&0\\0&0\end{array}} \right]$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from 3 and 4 . determinant and metrices→3 and 4 . determinant and metrices — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

The function $S(x) =\int\limits_0^x {\sin \left( {\frac{{\pi {t^2}}}{2}} \right)\,dt} $ has two critical points in the interval $[1, 2.4]$. One of the critical points is a local minimum and the other is a local maximum. The local minimum occurs at $x =$
→
Suppose that a function $f: R \rightarrow R$ satisfies $f(x+y)=f(x) f(y)$ for all $x, y \in R$ and $f(1)=3 .$ If $\sum \limits_{i=1}^{n} f(i)=363,$ then $n$ is equal to
→
If $f(x) = {\cot ^{ - 1}}\left( {{{{x^x} - {x^{ - x}}} \over 2}} \right)\,,$ then $f'(1)$ is equal to
→
If $\text{f(x)}=\begin{cases}\frac{|\text{x}+2|}{\tan^{-1}(\text{x}+2)}, & \text{x}\neq-2\\2, & \text{x}=-2\end{cases},$ then f(x) is:
  1. Continuous at x = -2
  2. Not continuous at x = -2
  3. Diffrentiable at x = -2
  4. Continuous but nit derivable at x = -2
→
$\tan ({\cos ^{ - 1}}x)$ is equal to
→
The solution of the equation $\frac{d y}{d x}=e^{x+y}+e^y x^2$ is :
→
Of the three independent events $E_1, E_2$ and $E_3$, the probability that only $E_1$ occurs is $\alpha$,only $E_2$ occurs is $\beta$ and only $E_3$ occurs is $\gamma$. Let the probability $p$ that none of events $E_1, E_2$ or $E_3$ occurs satisfy the equations ( $\alpha$ $-2 \beta) p=\alpha \beta$ and $(\beta-3 \gamma) p=2 \beta \gamma$. All the given probabilities are assumed to lie in the interval $(0,1)$.

Then $\frac{\text { Probability of occurrence of } E_1}{\text { Probability of occurrence of } E_3}=$

→
If $x - 2y = 4,$ the minimum value of $xy$ is
→
Inverse of the matrix $\left( {\begin{array}{*{20}{c}}1&{ - 2}\\3&4\end{array}} \right)$ is
→
If $A$ and $B$ are two events such that $P ( A )=\frac{1}{3}, P ( B )=\frac{1}{5} $ and $P ( A \cup B )=\frac{1}{2}$, then $P \left( A \mid B ^{\prime}\right)+ P \left( B \mid A ^{\prime}\right)$ is equal to
→