If A = [ * 20 c 0&2&0 0&0&3 - 2 &2&0 ]and B = [ * 20 c 1&2&3 3&4&… - Vidyadip

MCQ

If $A = \left[ {\begin{array}{*{20}{c}}0&2&0\\0&0&3\\{ - 2}&2&0\end{array}} \right]$and $B = \left[ {\begin{array}{*{20}{c}}1&2&3\\3&4&5\\5&{ - 4}&0\end{array}} \right]$, then the element of $3^{rd}$ row and third column in $AB$ will be

A
$-18$
✓
$4$
C
$-12$
D
None of these

✓

Answer

Correct option: B.

$4$

b
(b) In the product $AB$, the required element
${C_{33}} = ( - 2)3 + 2.5 + 0.0 = - 6 + 10 = 4$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

JEE STD 11 Science question papers→Gujarat Board STD 11 Science question papers→Gujarat Board question paper generator→

Similar questions

Let $y=y(x)$ be the solution of the differential equation $(x+1) y^{\prime}-y=e^{3 x}(x+1)^{2}$, with $y(0)=\frac{1}{3}$. Then, the point $x=-\frac{4}{3}$ for the curve $y = y ( x )$ is

If roots of the equation $a(b - c){x^2} + b(c - a)x + c(a - b) = 0$ are equal, then $a,\,b,\,c$ are in

Let three vectors $\overrightarrow{\mathrm{a}}=\alpha \hat{\mathrm{i}}+4 \hat{\mathrm{j}}+2 \hat{\mathrm{k}}$, $\vec{b}=5 \hat{i}+3 \hat{j}+4 \hat{k}, \vec{c}=x \hat{i}+y \hat{j}+z \hat{k}$ from a triangle such that $\overrightarrow{\mathrm{c}}=\overrightarrow{\mathrm{a}}-\overrightarrow{\mathrm{b}}$ and the area of the triangle is $5 \sqrt{6}$. if $\alpha$ is a positive real number, then $|\overrightarrow{\mathrm{c}}|^2$ is :

Let $\overrightarrow{ c }$ be a vector perpendicular to the vectors $\overrightarrow{ a }=\hat{ i }+\hat{ j }-\hat{ k }$ and $\overrightarrow{ b }=\hat{ i }+2 \hat{ j }+\hat{ k }.$

If $\overrightarrow{ c } \cdot(\hat{ i }+\hat{ j }+3 \hat{ k })=8$ then the value of $\overrightarrow{ c } \cdot(\overrightarrow{ a } \times \overrightarrow{ b })$ is equal to ...... .

The length of the latus rectum of the ellipse $\frac{{{x^2}}}{{36}} + \frac{{{y^2}}}{{49}} = 1$

The value of $x$ that satisfies the relation $x = 1 - x + x^2 - x^3 + x^4 - x^5 + ......... \infty$

A common tangent $T$ to the curves $C_{1}: \frac{x^{2}}{4}+\frac{y^{2}}{9}=1$ and $C_{2}: \frac{x^{2}}{42}-\frac{y^{2}}{143}=1$ does not pass through the fourth quadrant. If $T$ touches $C _{1}$ at ( $\left.x _{1}, y _{1}\right)$ and $C _{2}$ at $\left( x _{2}, y _{2}\right)$, then $\left|2 x _{1}+ x _{2}\right|$ is equal to $......$

If $\alpha,-\frac{\pi}{2}<\alpha<\frac{\pi}{2}$ is the solution of $4 \cos \theta+5 \sin \theta=1$, then the value of $\tan \alpha$ is

Let $g: R \rightarrow R$ be a non constant twice differentiable such that $g^{\prime}\left(\frac{1}{2}\right)=g^{\prime}\left(\frac{3}{2}\right)$. If a real valued function $f$ is defined as $\mathrm{f}(\mathrm{x})=\frac{1}{2}[\mathrm{~g}(\mathrm{x})+\mathrm{g}(2-\mathrm{x})]$, then

If $f(x) = \left\{ {\begin{array}{*{20}{c}}{\frac{{1 - \sin x}}{{\pi - 2x}},}&{x \ne \frac{\pi }{2}}\\{\,\,\,\,\,\,\,\,\,\,\,\,\,\lambda \,,}&{x = \frac{\pi }{2}}\end{array}} \right.$, be continuous at $x = \pi /2,$ then value of $\lambda $ is