MCQ
If $A = \left[ {\begin{array}{*{20}{c}}0&2&0\\0&0&3\\{ - 2}&2&0\end{array}} \right]$and $B = \left[ {\begin{array}{*{20}{c}}1&2&3\\3&4&5\\5&{ - 4}&0\end{array}} \right]$, then the element of $3^{rd}$ row and third column in $AB$ will be
  • A
    $-18$
  • $4$
  • C
    $-12$
  • D
    None of these

Answer

Correct option: B.
$4$
b
(b) In the product $AB$, the required element
${C_{33}} = ( - 2)3 + 2.5 + 0.0 = - 6 + 10 = 4$.

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