MCQ
If $A = \left[ {\begin{array}{*{20}{c}}{1/3}&2\\0&{2x - 3}\end{array}} \right],B = \left[ {\begin{array}{*{20}{c}}3&6\\0&{ - 1}\end{array}} \right]$and $AB = I$, then $x =$
- A$-1$
- ✓$1$
- C$0$
- D$2$
(As given)
$\Leftrightarrow \,\,3 - 2x = 1$ or $x = 1$.
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$(A)$ $1$ $(B)$ $2$ $(C)$ $3$ $(D)$ $4$
$f(x) = \left\{ {\begin{array}{*{20}{c}}
{{x^2} + 2mx - 1\,,}&{x \leq 0}\\
{mx - 1\,\,\,\,\,\,\,\,\,\,\,\,\,,}&{x > 0}
\end{array}} \right.$
If $f (x)$ is one-one then the set of values of $'m'$ is