If A = [ * 20 c 1& - 2 3&0 ], B = [ * 20 c - 1 &4 2&3 ], C = [ * … - Vidyadip

MCQ

If $A = \left[ {\begin{array}{*{20}{c}}1&{ - 2}\\3&0\end{array}} \right],$ $B = \left[ {\begin{array}{*{20}{c}}{ - 1}&4\\2&3\end{array}} \right]$, $C = \left[ {\begin{array}{*{20}{c}}0&{ - 1}\\1&0\end{array}} \right]$, then $5A - 3B - 2C$=

A
$\left[ {\begin{array}{*{20}{c}}8&{20}\\7&9\end{array}} \right]$
✓
$\left[ {\begin{array}{*{20}{c}}8&{ - 20}\\7&{ - 9}\end{array}} \right]$
C
$\left[ {\begin{array}{*{20}{c}}{ - 8}&{20}\\{ - 7}&9\end{array}} \right]$
D
$\left[ {\begin{array}{*{20}{c}}8&7\\{ - 20}&{ - 9}\end{array}} \right]$

✓

Answer

Correct option: B.

$\left[ {\begin{array}{*{20}{c}}8&{ - 20}\\7&{ - 9}\end{array}} \right]$

b
(b) $5A - 3B + 2C = \left[ {\begin{array}{*{20}{c}}5&{ - 10}\\{15}&0\end{array}} \right] - \left[ {\begin{array}{*{20}{c}}{ - 3}&{12}\\6&9\end{array}} \right] - \left[ {\begin{array}{*{20}{c}}0&{ - 2}\\2&0\end{array}} \right]$

$ = \left[ {\begin{array}{*{20}{c}}5&{ - 10}\\{15}&0\end{array}} \right] - \left[ {\begin{array}{*{20}{c}}{ - 3}&{10}\\8&9\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}8&{ - 20}\\7&{ - 9}\end{array}} \right]$.

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