If a simple harmonic oscillator has got a displacement of $0.02\, m$ and acceleration equal to $2.0\,m{s^{ - 2}}$ at any time, the angular frequency of the oscillator is equal to .... $rad\,{s^{ - 1}}$
AIPMT 1992, Easy
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(a) $\omega = \sqrt {\frac{{Acceleration}}{{Displacement}}} $
$ = \sqrt {\frac{{2.0}}{{0.02}}} $
$ = 10\,rad\;{s^{ - 1}}$
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