MCQ
If $a,\;b,\;c,\;d$ are positive, then $\mathop {\lim }\limits_{x \to \infty } {\left( {1 + \frac{1}{{a + bx}}} \right)^{c + dx}} = $
- ✓${e^{d/b}}$
- B${e^{c/a}}$
- C${e^{(c + d)/(a + b)}}$
- D$e$
$= \mathop {\lim }\limits_{x \to \infty } \,{\left\{ {{{\left( {1 + \frac{1}{{a + bx}}} \right)}^{a + bx}}} \right\}^{\frac{{c + dx}}{{a + bx}}}} = {e^{d/b}}$
$\left\{ {\because \,\,\mathop {\lim }\limits_{x \to \infty } \,{{\left( {1 + \frac{1}{{a + bx}}} \right)}^{a + bx}} = e} \right.$ and
$\left. {\mathop {\lim }\limits_{x \to \infty } \frac{{c + dx}}{{a + bx}} = \frac{d}{b}} \right\}$.
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$(A)$ $\frac{\pi}{2}$ $(B)$ $\frac{\pi}{6}$ $(C)$ $\frac{2 \pi}{3}$ $(D)$ $\frac{5 \pi}{6}$