MCQ
If $\alpha + \beta = \frac{\pi }{2}$ and $\beta + \gamma = \alpha ,$ then $\tan \,\alpha $ equals
  • A
    $2\,(\tan \beta + \tan \gamma )$
  • B
    $\tan \beta + \tan \gamma $
  • $\tan \beta + 2\,\tan \gamma $
  • D
    $2\,\tan \beta + \tan \gamma $

Answer

Correct option: C.
$\tan \beta + 2\,\tan \gamma $
c
(c)$\alpha + \beta = \frac{\pi }{2} \Rightarrow \tan \beta = \cot \alpha $
$\tan (\beta + \gamma ) = \tan \alpha $ ==> $\tan \alpha = \frac{{\tan \beta + \tan \gamma }}{{1 - \tan \beta \tan \gamma }}$
==> $\tan \alpha = \frac{{\cot \alpha + \tan \gamma }}{{1 - \cot \alpha \tan \gamma }}$
==> $\tan \alpha - \tan \gamma = \cot \alpha + \tan \gamma $
==> $\tan \alpha = \tan \beta + 2\tan \gamma $.

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