MCQ
If $\angle\text{AOB}=40^\circ,$ then the measure of $\angle\text{ACB}$ is:
- A$20^\circ$
- B$80^\circ$
- ✓$50^\circ$
- D$40^\circ$
✓
Answer
Correct option: C.
$50^\circ$
In triangle $ABC,$
$\angle\text{A}+\angle\text{B}+\angle\text{C}=180^\circ$
$40^\circ+90^\circ+\angle\text{C}=180^\circ$
$\angle\text{C}=50^\circ$
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