Question
If $\begin{bmatrix}\text{x}&1 \end{bmatrix}\begin{bmatrix}1&0\\-2&0 \end{bmatrix}=0,$ find x.

Answer

$\begin{bmatrix}\text{x}&1 \end{bmatrix}\begin{bmatrix}1&0\\-2&0 \end{bmatrix}=0$
$\Rightarrow\begin{bmatrix}\text{x}-2&0+0 \end{bmatrix}=\begin{bmatrix}0&0 \end{bmatrix}$
$\Rightarrow\begin{bmatrix}\text{x}-2&0 \end{bmatrix}=\begin{bmatrix}0&0 \end{bmatrix}$ 
$\Rightarrow\text{x}-2=0$
$\Rightarrow\text{x}=2$
$\therefore\text{x}=2.$

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