MCQ
If $C = 2\cos \theta $, then the value of the determinant $\Delta = \left| {\,\begin{array}{*{20}{c}}C&1&0\\1&C&1\\6&1&C\end{array}\,} \right|$ is
  • A
    $\frac{{\sin 4\theta }}{{\sin \theta }}$
  • B
    $\frac{{2{{\sin }^2}2\theta }}{{\sin \theta }}$
  • C
    $4{\cos ^2}\theta \,(2\cos \theta - 1)$
  • None of these

Answer

Correct option: D.
None of these
d
(d) $\Delta = \left| {\,\begin{array}{*{20}{c}}C&1&0\\1&C&1\\6&1&C\end{array}\,} \right|\, = C[{C^2} - 1] - 1[C - 6]$

==> $\Delta = 2\cos \theta (4{\cos ^2}\theta - 1) - (2\cos \theta - 6)$
==> $\Delta = 8{\cos ^3}\theta - 4\cos \theta + 6$.

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