MCQ
If concentration of reactants is increased by $'x'$, then $K$ becomes
- Aln ($K/x$)
- B$K/x$
- C$K + x$
- ✓$K$
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$B.E(N -N) = 159\, kJ\, mol^{-1}$,
$B.E(H -H) = 436\, kJ\, mol^{-1}$
$B.E.(N \equiv N) = 941\, kJ\, mol^{-1}$,
$B.E(N -H) = 398\, kJ\, mol^{-1}\, .......\,kJ\, mol^{-1}$