MCQ
If ${e^x} = y + \sqrt {1 + {y^2}} $, then $y =$
- A$\frac{{{e^x} + {e^{ - x}}}}{2}$
- ✓$\frac{{{e^x} - {e^{ - x}}}}{2}$
- C${e^x} + {e^{ - x}}$
- D${e^x} - {e^{ - x}}$
$\therefore$ ${e^x} - y = \sqrt {1 + {y^2}} $
Squaring both the sides, ${({e^x} - y)^2} = (1 + {y^2})$
${e^{2x}} + {y^2} - 2y{e^x} = 1 + {y^2} \Rightarrow {e^{2x}} - 1 = 2y{e^x}$
==> $2y = \frac{{{e^{2x}} - 1}}{{{e^x}}} \Rightarrow 2y = {e^x} - {e^{ - x}}$
Hence, $y = \frac{{{e^x} - {e^{ - x}}}}{2}$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| Column-$I$ | Column-$II$ |
| $(A)$ In a triangle $\triangle X Y Z$, let $a, b$ and $c$ be the lengths of the sides opposite to the angles $X, Y$ and $Z$, respectively. If $2\left(a^2-b^2\right)=c^2$ and $\lambda=\frac{\sin (X-Y)}{\sin Z}$, then possible values of $n$ for which $\cos ( n \pi \lambda)=0$ is (are) | $(P)$ $1$ |
| $(B)$ In a triangle $\triangle X Y Z$, let $a, b$ and $c$ be the lengths of the sides opposite to the angles $X, Y$ and $Z$, respectively. If $1+\cos 2 X-$ $2 \cos 2 Y=2 \sin X \sin Y$, then possible value(s) of $\frac{a}{b}$ is (are) | $(Q)$ $2$ |
| $(C)$ In $R ^2$, let $\sqrt{3} \hat{i}+\hat{j}, \hat{i}+\sqrt{3} \hat{j}$ and $\beta \hat{i}+(1-\beta) \hat{j}$ be the position vectors of $X, Y$ and $Z$ with respect of the origin $O$, respectively. If the distance of $Z$ from the bisector of the acute angle of $\overline{O X}$ with $\overline{O Y}$ is $\frac{3}{\sqrt{2}}$, then possible value(s) of $|\beta|$ is (are) | $(R)$ $3$ |
| $(D)$ Suppose that $F(\alpha)$ denotes the area of the region bounded by $x=$ $0, x=2, y^2=4 x$ and $y=|\alpha x-1|+|\alpha x-2|+\alpha x$, where $\alpha \in\{0$, 1\}. Then the value(s) of $F(\alpha)+\frac{8}{3} \sqrt{2}$, when $\alpha=0$ and $\alpha=1$, is (are) | $(S)$ $5$ |
| $(T)$ $6$ |