MCQ
If f′ (0) = 0 and f(x) is a differentiable and increasing function,then $\lim\text{x}\rightarrow0 \ \frac{\text{x},\text{f(x)}^2}{\text{f(x)}}$:
  • A
    Is always equal to zero
  • B
    May not exist as left hand limit may not exist
  • C
    May not exist as left hand limit may not exist
  • D
    Right hand limit is always zero

Answer

  1. Is always equal to zero

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The ratio in which xy-plane divides the line joining the points (1, 0, -3) and (1, -5, 7) is given by:

If two coins are tossed then find the probability of the events that at the most one tail turns up:

A point C with position vector $\frac{\text{3a}+4\text{b}-5\text{c}}{3}$ (where a, b and c are non co-planar vectors) divides the line joining A and B in the ratio 2 : 1. If the position vector of A is a - 2b + 3c, then the position vector of B is:
If a be A.M. and p, q be two G.M.'s between two numbers, then 2A is equal to:
If $(x, 3)(3,5)$ be the ends of the diameter of a circle having centre at $(2, y)$, values of $x$ and $y$ are :
If $f(x)=x \sin x$, then $f^{\prime}\left(\frac{\pi}{2}\right)$ is equal to
In a school with an envolment of 950 students, each student must join either the lions club or the country club or both. Given that 646 students are members of the lions club and 532 are members of the country club, calculate the number of students who are members of both clubs:
If $3\text{f(x)}+5\text{f}\Big(\frac{1}{\text{x}}\Big)=\frac{1}{\text{x}}-3$ for all non-zero x, then f(x) =
  1. $\frac{1}{14}\Big(\frac{3}{\text{x}}+5\text{x}-6\Big)$
  2. $\frac{1}{14}\Big(-\frac{3}{\text{x}}+5\text{x}-6\Big)$
  3. $\frac{1}{14}\Big(-\frac{3}{\text{x}}+5\text{x}+6\Big)$
  4. None os these.
If ${^\text{20}}\text{C}_{\text{r}}={^\text{20}}\text{C}_{\text{r+4}}$ is then ${^\text{r}}\text{C}_{\text{3}}$ equal to:
If $\frac{\big[\text{x} – 7\big]}{(\text{x} – 7)\geq 0}$ then: