Question
If $f : R \rightarrow (0, 2)$ defined by $\text{f(x)}=\frac{\text{e}^{\text{x}}-\text{e}^{-\text{x}}}{\text{e}^{\text{x}}+\text{e}^{-\text{x}}}+1$ is invertible, find $f^{-1}.$

Answer

$\text{A}=\{\text{x}\in\text{R}:-1\leq\text{x}\leq1\}$ and $f : A \rightarrow A, g : A \rightarrow A$ are two functions defined by $f(x) = x^2 $ and $\text{g(x)}=\sin\Big(\frac{\pi\text{x}}{2}\Big)$
Here, $f : A \rightarrow A$ is defined by
$f(x) = x^2$
Clearly f in not injective,
$\because\ \text{f}(1)=\text{f}(-1)=1$
So, $f$ is not bijective and hence not invertible.
Hence, $f^{-1}$ does not exist.

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