MCQ
If $f(x) = \left\{ \begin{array}{l}\frac{{{x^2} + 3x - 10}}{{{x^2} + 2x - 15}},\;\;{\rm{when \,\,}}x \ne - 5\\\,\,a\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,,{\rm{when\,\, }}x = - 5\end{array} \right.$   $x = - 5$ is continuous at $x = - 5$, then the value of $'a'$ will be
  • A
    $\frac{3}{2}$
  • $\frac{7}{8}$
  • C
    $\frac{8}{7}$
  • D
    $\frac{2}{3}$

Answer

Correct option: B.
$\frac{7}{8}$
b
(b) $\mathop {\lim }\limits_{x \to \, - \,5} f(x) = \frac{{(x - 2)\,\,(x + 5)}}{{(x + 5)\,(x - 3)}} = \frac{{ - 7}}{{ - 8}} = \frac{7}{8}.$

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