MCQ
If $f(x) = \left\{ \begin{array}{l}x\sin \frac{1}{x},\,\,x \ne 0\\\,\,\,\,\,\,\,\,\,\,\,\,k,\,\,x = 0\end{array} \right.$ is continuous at $x = 0$, then the value of $k$ is
  • A
    $1$
  • B
    $-1$
  • C
    $0$
  • D
    $2$

Answer

If function $f(x)$ is continuous at $x = 0,$ then
$f(0) = \mathop {\lim }\limits_{x \to 0} \,f(x)$
Given $f(0) = k ; f(0) = k = \mathop {\lim }\limits_{x \to 0} \,x\,\left( {\sin \frac{1}{x}} \right)$
$f(0) = k = 0,{\rm{ }}\left( { - 1 \le \sin \frac{1}{x} \le 1} \right)$; 
$\therefore k = 0$.

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