If f(x)= ^2 x and the composite function g(f(x))=| x|, then g(x) … - Vidyadip

MCQ

If $f(x)=\sin ^2 x$ and the composite function $g(f(x))=|\sin x|$, then $g(x)$ is equal to:

A
$\sqrt{\text{x}-1}$
✓
$\sqrt{\text{x}}$
C
$\sqrt{\text{x}+1}$
D
$-\sqrt{\text{x}}$

✓

Answer

Correct option: B.

$\sqrt{\text{x}}$

Given that $\text{f(x)}=\sin^2\text{x}$ and the composite function $\text{g(f(x))}=|\sin\text{x}|$
We will do it using trial and error method.
If we take $\text{g(x)}=-\sqrt{\text{x}}$ and $\text{f(x)}=\sin^2\text{x}$
$\text{g(f(x))}=\text{g}(\sin^2\text{x})$
$=-\sin\text{x}$
Which contradicts to the $\text{g(f(x))}=|\sin\text{x}|$
Hence, we take $\text{g(x)}=\sqrt{\text{x}}$
$\text{g(f(x))}=\text{g}(\sin^2\text{x})$
$=\sqrt{\sin^2\text{x}}=|\sin\text{x}|$

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