MCQ
If $f(x) = x, - 1 \le x \le 1$, then function $f(x)$ is
- ✓Increasing
- BDecreasing
- CStationary
- DDiscontinuous

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y = vx
v = yx
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x = v
$PROPERTY 1$ if $\lim _{ h \rightarrow 0} \frac{ f ( h )- f (0)}{\sqrt{| h |}}$ exists and is finite, and $PROPERTY 2$ if $\lim _{h \rightarrow 0} \frac{f(h)-f(0)}{h^2}$ exists and is finite.
Then which of the following options is/are correct ?
$(1)$ $f(x)=x|x|$ has $PROPERTY$ $2$ $(2)$ $f(x)=x^{2 / 3}$ has $PROPERTY$ $1$ $(3)$ $f(x)=\sin x$ has $PROPERTY$ $2$ $(4)$ $f(x)=|x|$ has $PROPERTY$ $1$