MCQ
If $f(x) = {x^2} - 1$ and $g(x) = 3x + 1$, then $(gof)(x) = $
- A${x^2} - 1$
- B$2{x^2} - 1$
- ✓$3{x^2} - 2$
- D$2{x^2} + 2$
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Let f : R → R be the functions defined by f(x) = x3 + 5. Then f-1(x) is: