If f(x)= ^ -1 [1-( x)^2 1+( x)^2 ], then f^ (e)= - Vidyadip

MCQ

If $f(x)=\cos ^{-1}\left[\frac{1-(\log x)^2}{1+(\log x)^2}\right]$, then $f^{\prime}(e)=$

✓
$\frac{1}{ e }$
B
$\frac{2}{ e ^2}$
C
1
D
$\frac{2}{ e }$

✓

Answer

Correct option: A.

$\frac{1}{ e }$

A

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