MCQ
If in a moderately asymmetrical distribution mode and mean of the data are $6$ $\lambda$ and $9$ $\lambda$ respectively, then median is
- ✓$8$ $\lambda$
- B$7$ $\lambda$
- C$6$ $\lambda$
- D$5$ $\lambda$
Mode = $3$ median -$2$ mean
==> $6\lambda $ = $3$ median -$18$ $\lambda $
==> median = $8\ \lambda $.
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