MCQ
If in $NH_3$ formation $N$ uses its pure atomic orbital then wrong statement is
- AAt least three bond angle are of $90^o$
- BThree $\sigma $ bond with identical strength
- CLone pair will be in $2s$ orbital
- ✓Molecule will be $T-$ shaped
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
${H_3}C - C \equiv CH\,\xrightarrow[{HgS{O_4}}]{{{H_2}O,\,{H_2}S{O_4}}}\,\mathop {Intermediate}\limits_{(A)} \,$$ \to \,\mathop {\Pr oduct}\limits_{(B)} $
