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Units, Dimensions and Measurement — JEE physics STD 12 Science — Question

CBSE BoardEnglish MediumSTD 12 ScienceJEE physicsUnits, Dimensions and Measurement1 Mark
MCQ
If $L=2.331 cm , B=2.1 cm$, then $L+B=$
  • A
    $4.431 cm$
  • B
    $4.43 cm$
  • C
    $4.4 cm$
  • ✓
    $4 cm$
✓

Answer

Correct option: D.
$4 cm$
(d)$\text { Kinetic energy } E=\frac{1}{2} m v^2$
$\therefore \frac{\Delta E}{E} \times 100=\frac{v^{\prime 2}-v^2}{v^2} \times 100 $
$=\left[(1.5)^2-1\right] \times100$
$\therefore \frac{\Delta E}{E} \times 100=125 \%$
(c) Quantity C has maximum power. So it brings maximum error in $P$.
(c) Given, $L=2.331 \mathrm{~cm}=2.33$ (correct upto two decimal places)and $B=2.1 \mathrm{~cm}=2.10 \mathrm{~cm}$$\therefore L+B=2.33+2.10=4.43 \mathrm{~cm} .=4.4 \mathrm{~cm}$Since minimum significantfigure is 2 .

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