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Complex Numbers — Maths STD 11 Science — Question

Maharashtra BoardEnglish MediumSTD 11 ScienceMathsComplex Numbers2 Marks
MCQ
If $\left(\frac{1- i }{1+ i }\right)^{96}= a + ib$, then $( a , b )$ is
  • A
    $(1,1)$
  • ✓
    $(1,0)$
  • C
    $(0,1)$
  • D
    $(0,-1)$
✓

Answer

Correct option: B.
$(1,0)$
(B)
$\left(\frac{1- i }{1+ i }\right)^{96}=\left(\frac{1- i }{1+ i } \times \frac{1- i }{1- i }\right)^{96}=(- i )^{96}=1=1+0 i$
$\therefore \quad(a, b)=(1,0)$

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