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3 and 4 . determinant and metrices — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMaths3 and 4 . determinant and metrices1 Mark
MCQ
If $\left| {\,\begin{array}{*{20}{c}}{x - 1}&3&0\\2&{x - 3}&4\\3&5&6\end{array}\,} \right| = 0$, then $x =$
  • A
    $0$
  • B
    $2$
  • C
    $3$
  • ✓
    $1$
✓

Answer

Correct option: D.
$1$
d
(d) Given equation reduces to $(x - 1)\,(6x - 38) = 0$

==> $3{x^2} - 22x + 19 = 0 \Rightarrow (x - 1)(3x - 19) = 0$

==> $x = 1,\,19/3$.

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