Question
If $\left(x^2+\frac{1}{x^2}\right)=7$, find the values of $\left(x-\frac{1}{x}\right)$
✓
Answer
$\pm \sqrt{5}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In the adjoining figure, equilateral $\triangle E D C$ surmounts square ABCD . If $\angle DEB =x^{\circ}$, find the value of $x$.
→Two parallel chords AB and CD are 3.9 cm apart and lie on the opposite sides of the centre of a circle. If $A B=1.4 cm$ and $CD =4 cm$, find the radius of the circle.
→Construct a quadrilateral ABCD in which AB = 3.2 cm, BC = 2.8 cm CD = 4 cm, DA = 4.5 cm and BD = 5.3 cm. Also construct a triangle equal in area to this quadrilateral.
Using a scale of $1 \ cm$ to $1$ unit for both the axes, draw the graphs of the following equations$: 6y = 5x + 10, y = 5x - 15.$From the graph find :$(i)$ the coordinates of the point where the two lines intersect;$(ii)$ the area of the triangle between the lines and the $x-$ axis.
→Solve : $\left[3^x\right]^2: 3 \mathrm{x}=9: 1$
→Which of the following pairs of triangles are congruent? Give reasons $\triangle ABC;(AB = 8\ cm,BC = 6\ cm,\angle B = 100^\circ );
\triangle PQR;(PQ = 8\ cm,RP = 5\ cm,\angle Q = 100^\circ ).$
→\triangle PQR;(PQ = 8\ cm,RP = 5\ cm,\angle Q = 100^\circ ).$
Draw the graph of the line $x + y = 5$. Use the graph paper drawn to find the inclination and the $y-$intercept of the line.
→The area of a rectangle gets reduced by $9$ square units, if its length is reduced by $5$ units and breadth is increased by $3$ units. However, if the length of this rectangle increases by $3$ units and the breadth by $2$ units, the area increases by $67$ square units. Find the dimensions of the rectangle.
→In the figure: $\angle PSQ =90^{\circ}, PQ =10 \ cm , QS =6 \ cm$ and $RQ =9 \ cm$. Calculate the length of $PR.$
→The circumference of a circle, with center $O,$ is divided into three arcs $\text{APB, BQC,}$ and $\text{CRA}$ such that:$\frac{\operatorname{arc} APB }{2}=\frac{\operatorname{arc} BQC }{3}=\frac{\operatorname{arc} CRA }{4}$Find $\angle BOC.$
→