Question
If $\log (a + 1) = \log (4a - 3) - \log 3;$ find $a.$

Answer

$\log (a + 1) = \log (4a - 3) - \log 3$
$\Rightarrow \log (a + 1) + \log 3 = \log (4a - 3)$
$\Rightarrow \log {3(a + 1)} = \log (4a - 3)$
$\Rightarrow 3 (a + 1) = 4a - 3$
$\Rightarrow 3a + 3 = 4a - 3$
$\Rightarrow 4a - 3a = 3 + 3$
$\Rightarrow a = 6.$

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