Question
If $m$ is a positive integer which is not a perfect cube, then $\sqrt[3]{\text{m}}$ is:
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Answer
A natural number is called a perfect cube if it is the cube of some natural number.
i.e., if $m = n^3,$ then $m$ is a perfect cube where $m$ and $n$ are natural numbers.
If $m$ is not a perfect cube then the number will be an irrational number because the value will be $\sqrt[3]{\text{m}}$ which cannot be written as a fraction or rational number.
i.e., if $m = n^3,$ then $m$ is a perfect cube where $m$ and $n$ are natural numbers.
If $m$ is not a perfect cube then the number will be an irrational number because the value will be $\sqrt[3]{\text{m}}$ which cannot be written as a fraction or rational number.
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