Question
If 'm' is a positive integer which is not a perfect square, then $\sqrt{\text{m}}$ is:
✓
Answer
- An irrational number.
Solution:
In $\sqrt{\text{m}}$ ,if m is not perfect square ,then the value of $\sqrt{\text{m}}$ will be $\text{m}^\frac{1}{2}.$
But if it is perfect square then value of $\sqrt{\text{m}}=$ some integer,
Example $\sqrt{4}=2$
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