Question
If $\mathrm{A}=\left[\begin{array}{lll}\mathrm{a}_{11} & \mathrm{a}_{12} & \mathrm{a}_{13}\end{array}\right]$ and $\mathrm{B}=\left[\begin{array}{l}b_{11} \\ b_{21} \\ b_{31}\end{array}\right]$ Find $A B$.

Answer

Since number of columns of $A=$ number of rows of $B=3$
Therefore product $\mathrm{AB}$ is defined and its order is $1 .$
$(A)_{1 \times 3}(B)_{3 \times 1}=(A B)_{1 \times 1}$
$A B=\left[a_{11} \times b_{11}+a_{12} \times b_{21}+a_{13} \times b_{31}\right]$

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