Therefore
${A^{16}} = {({A^2})^8} = {\left[ {\begin{array}{*{20}{c}}{ - 1}&0\\0&{ - 1}\end{array}} \right]^8} = \left[ {\begin{array}{*{20}{c}}{{{( - 1)}^8}}&0\\0&{{{( - 1)}^8}}\end{array}} \right]$$ = \left[ {\begin{array}{*{20}{c}}1&0\\0&1\end{array}} \right]$.
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$($ where $n \in I)$
${l_1} = \left( {3 + t} \right)\hat i + \left( { - 1 + 2t} \right)\hat j + \left( {4 + 2t} \right)\hat k,\, - \infty < t < \infty $
${l_2} = \left( {3 + 2s} \right)\hat i + \left( {3 + 2s} \right)\hat j + \left( {2 + s} \right)\hat k,\, - \infty < s < \infty $
Statement $1$ : Line $l$ and $l_2$ are coplaner lines
Statement $2$ : Line $l$ and $l_2$ are intersecting lines