MCQ
If $M.D.$ is $12$, the value of $S.D.$ will be
- ✓$15$
- B$12$
- C$24$
- DNone of these
${\rm{S}}{\rm{.D}}{\rm{.}} = \frac{3}{2} \times {\rm{Q}}{\rm{.D}}{\rm{.}}$
$ = \frac{3}{2} \times 10$
==> ${\rm{S}}{\rm{.D}}{\rm{.}} = 15$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$A=\left\{(x, y) \in R \times R \mid 2 x^{2}+2 y^{2}-2 x-2 y=1\right\}$
$B=\left\{(x, y) \in R \times R \mid 4 x^{2}+4 y^{2}-16 y+7=0\right\} \text { and }$
$C=\left\{(x, y) \in R \times R \mid x^{2}+y^{2}-4 x-2 y+5 \leq r^{2}\right\}$
Then the minimum value of $|r|$ such that $A \cup B \subseteq C$ is equal to:
