MCQ
If $n$ is a positive integer greater than unity and $z$ is a complex number satisfying the equation ${z^n} = {(z + 1)^n}$, then
  • ${\mathop{\rm Re}\nolimits} (z) < 0$
  • B
    ${\mathop{\rm Re}\nolimits} (z) > 0$
  • C
    ${\mathop{\rm Re}\nolimits} (z) = 0$
  • D
    None of these

Answer

Correct option: A.
${\mathop{\rm Re}\nolimits} (z) < 0$
a
(a)We have ${z^n} = {(1 + z)^n}\,\,\, \Rightarrow {\left( {\frac{z}{{z + 1}}} \right)^n} = 1$
==> $\frac{z}{{z + 1}} = {1^{1/n}}$

==> $\frac{z}{{z + 1}}$is a $n$th root of unity
==> $\left| {\frac{z}{{z + 1}}} \right| = 1$==>$\frac{{|z|}}{{|z + 1|}} = 1$

==> $|z|\, = \,|z + 1|$
==> $x + \frac{1}{2} = 0$==> $x = \frac{{ - 1}}{2}$

==> ${\mathop{\rm Re}\nolimits} (z) < 0$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

The locus of mid point of that chord of parabola ${y^2} = 4ax$ which subtends right angle on the vertex will be
A circle ${x^2} + {y^2} + 2gx + 2fy + c = 0$ passing through $(4,\; - 2)$ is concentric to the circle ${x^2} + {y^2} - 2x + 4y + 20 = 0$, then the value of $c$ will be
$\mathop {\lim }\limits_{x \to 0} \frac{{{e^{\sin x}} - 1}}{x} = $
The sum of $n$ terms of the following series $1 + (1 + x) + (1 + x + {x^2}) + ..........$ will be
The number of $6$ digit numbers that can be formed using the digits $0, 1, 2, 5, 7$ and $9$ which are divisible by $11$ and no digits is repeated, is
Let a circle $C$ of radius $5$ lie below the $x$-axis. The line $L_{1}=4 x+3 y-2$ passes through the centre $P$ of the circle $C$ and intersects the line $L _{2}: 3 x -4 y -11=0$ at $Q$. The line $L _{2}$ touches $C$ at the point $Q$. Then the distance of $P$ from the line $5 x-12 y+51=0$ is
If the constant term in the binomial expansion of $\left(\frac{x^{\frac{5}{2}}}{2}-\frac{4}{x^{\ell}}\right)^9$ is $-84$ and the Coefficient of $x^{-3 \ell}$ is $2^\alpha \beta$, where $\beta < 0$ is an odd number, Then $|\alpha \ell-\beta|$ is equal to
In set-builder method the null set is represented by:
If $\frac{(1-3\text{P})}{2},\frac{(1+4\text{P})}{3},\frac{(1+\text{P})}{6}$ are the probabilities of three mutually exclusive and exhaustive events, then the set of all values of p is:
$A(a,0)$ and $B( - a,0)$ are two fixed points of triangle $ABC$. The vertex $C$ moves in such a way that $\cot A + \cot B = \lambda ,$ where $\lambda $ is a constant. Then the locus of the point $C$ is