MCQ
If $^n{P_r}$=$ 720$.$^n{C_r},$ then $r$ is equal to
- ✓$6$
- B$5$
- C$4$
- D$7$
==> $^n{P_r}\, \div {\,^n}{C_r}\, = 720$
==> $\,r\,! = 720 = 6\,!$
$==> r = 6.$
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Where $\alpha \in R$, then the value of $16 \alpha$ is equal to