MCQ
If $\overrightarrow P .\overrightarrow Q = PQ,$ then angle between $\overrightarrow P $and $\overrightarrow Q $ is ....... $^o$
- ✓$0$
- B$30$
- C$45$
- D$60$
✓
Answer
Correct option: A.
$0$
a
(a) $\cos \theta = \frac{{\vec P.\vec Q}}{{PQ}} = 1$
(a) $\cos \theta = \frac{{\vec P.\vec Q}}{{PQ}} = 1$
$\theta = 0^\circ $
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